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fundamentals of mathematics

Types of progression (AP,GP,HP progression)

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Types of progression

A progression is a sequence of numbers following a specific pattern. The most common types of progression are:

Arithmetic Progression

An arithmetic progression is a sequence of numbers in which the difference between consecutive terms is constant. This constant difference is called the common difference (d).

1. General form of an AP: An arithmetic sequence is written as

a, a+d, a+2d, a+3d+…

Where

  • a=first term
  • d=common difference
  • n=number of terms
  • l=last term

2. The nth term of an AP is given by

Types of progression

3. Sum of first n terms

The sum of the first n terms is

Or,

Types of progression

Example 1: Find the 10th term of the AP: 3, 7, 11, 15,…

Here,

a=3, d=7-3=4, n=10

Using:

Types of progression

So, the 10th term is 39.

Example 2: Find the sum of the first 20 terms of the AP: 5, 8, 11, 14,…

Here,

a=5,d=8-5=3,n=20

Using

Types of progression

So the sum of the first 20 terms is 670.

Geometric Progression

A geometric progression is a sequence of numbers where each term is obtained by multiplying the previous term by a fixed constant called the common ratio (r).

General form of a GP

Where

  • a=first term
  • r=common ratio
  • n=number of terms

1.nth term of a GP:

2. Sum of first n terms of a GP

Types of progression

3. Sum of infinite GP(|r| < 1)

If ∣r∣<1, the infinite sum converges to:

Types of progression

Example 1: Find the 12th term of the GP: 5, 10, 20, 40, 80,…

Here,

a=5, r=10/5=2

Using

Types of progression

Types of progression

Example 2: Find the sum of the first 12 terms of the GP: 5, 10, 20, 40, 80,…

a=5,r=10/5=2

Using

Types of progression

 

Harmonic Progression

A harmonic progression is a sequence of numbers whose reciprocals form an Arithmetic progression (AP)

General form of an HP

1. nth term of HP

2. The sum of the first terms of the harmonic progression is:

Example 1: Find the 5th term of the HP: 3, 6, 9, 12,…

Here,

a=3, d=3

First find the 5th term of the HP

A5=a+(n1)d=3+(51)×3=3+12=15

Now, the 5th term of the HP is:

Special algebraic series

i) Sum of First n natural numbers:

Types of progression

ii) Sum of First n squares

iii) Sum of first n cubes

 

 

 

 

 

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fundamentals of mathematics

Polynomial synthetic division examples

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Polynomial synthetic division

Polynomial synthetic division

Synthetic division is a simplified and fast method for dividing a polynomial by a linear divisor of the type  x−c. It eliminates the requirement for lengthy division, making the operation faster and simpler, particularly for higher-degree polynomials. Here’s an explanation of how Polynomial synthetic division works, followed by an illustration.

Steps for Synthetic Division

Given a polynomial

Set up the coefficients: Record the coefficients of the polynomial P(x) in a row. If any powers of  x are absent (e.g., no 𝑥 2  phrase), include a zero for that term.

Write the root of the divisor: The divisor x−cx – c means the root is cc. This is the value you’ll use for the division.

Perform synthetic division:

  • Bring down the first coefficient as it is.
  • Multiply the result by 𝑐 and add it to the following coefficient.
  • Repeat the method for each coefficient.

Interpret the results:

  • The last number in the row is the remainder.
  • The other numbers are the quotient’s coefficients.

Polynomial synthetic division examples: Divide

Polynomial synthetic division

Step-by-step process

1. Write the coefficients: The polynomial 2x^3 – 3x^2 + 4x – 5 has the coefficients .

2. Set up the synthetic division table:To divide by x−1, use 𝑐 = 1 .

Polynomial synthetic division

3. Begin the synthetic division:

  • Bring down the first coefficient (2).
  • Multiply 2 by 1 (the root of the divisor x – 1) to obtain 2.
  • Add this to the following coefficient:− 3 + 2 = − 1
  • Multiplying -1 by 1 yields -1.
  • Add this to the following coefficient: 4 + ( − 1 ) = 3 .
  • Multiply 3 by 1 to get three.
  • Add this to the final coefficient: −5 + 3 = −2

The synthetic division table now looks like this:

Polynomial synthetic division

4. Interpret the results:

The quotient is  2x^ 2 -x+3.
The remaining is -2.

Thus, the division gives:

Polynomial synthetic division

Important Points:
Quotient: The quotient’s coefficients are  2x^2 −x+3.
remaining:  -2 is the remaining.
Interpretation: This indicates that P(x)=(x−1)(2x^ 2 −x+3)−2, indicating that the division was correct with the exception of −2.

Why It Works:

Synthetic division uses the remainder theorem and polynomial properties to divide by a linear term ( x – c). Rather than going through the long division procedure step by step, synthetic division integrates all of the processes into a more compact form.

 

 

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fundamentals of mathematics

Complex Arithmetic

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A complex number is one that takes the concept of numbers beyond the real number line. It consists of two parts: actual and imaginary.Four main features of complex arithmetic—modulus, argument, addition, and multiplication—will be discussed in this blog. It is often written in the following format:

1. The modulus of a complex number: The modulus of a complex number ∣z∣ indicates its distance from the origin (0, 0) in the complex plane. The modulus of a complex number (𝑧=𝑎+𝑏) is determined mathematically as follows:

Example: For the complex number z=3+4i, the modulus is calculated as:

This indicates that there are 5 units separating the origin from the point (3,4) in the complex plane.

2. Argument of a complex number:

The argument of a complex number is the angle θ\theta that the complex number makes with the positive real axis in the complex plane. For , the argument θ is defined as:

Complex Arithmetic

Quadrant Considerations:

  • Quadrant I (both a and b positive):

Complex Arithmetic

  • Quadrant II ( a negative, b positive):

  • Quadrant III (both a and b negative):

Complex Arithmetic

  • Quadrant IV ( a positive, b negative):

Addition of complex number:

The addition of complex numbers is simple: add their real and imaginary parts.

If two complex numbers are given as:

Then their sum is

Steps for Addition

  • Add the real parts: a+c
  • Add the imaginary parts: b+d
  • Combine the results into the form : (a+c)+(b+d)i

Example:

Complex Arithmetic

Mutiplication of two complex numbers:

Two complex numbers multiply using the distributive property and simplify depending on the knowledge that i^ 2 = −1.

If two complex numbers are

Then their product is:

By expanding the product:

Since i^2 = 1, the expression simplifies to:

Complex Arithmetic

Example:

Complex Arithmetic

Complex Arithmetic

Simplify i^2=-1:

Complex Arithmetic

Understanding the modulus and argument provides a geometric perspective of complex arithmetic, while addition and multiplication reveal their algebraic properties.

 

 

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