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Cauchy schwarz inequality proof

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Cauchy schwarz inequality

Statement (Cauchy-Schwarz Inequality):

For any two vectors 𝑢 = ( 𝑢 _1 , 𝑢_ 2 , … , 𝑢_ 𝑛 ) and 𝑣 = ( 𝑣 _1 , 𝑣 _2 , … , 𝑣 _𝑛 ), the Cauchy-Schwarz inequality states:

Cauchy schwarz inequality

with equality if and only if the vectors are linearly dependent. That is, one vector is a scalar multiple of another.

This inequality limits the magnitude of the dot product of two vectors, laying the groundwork for numerous mathematical notions such as vector angle and orthogonality.

Proof:

1. Applying the concept of quadratic forms:

The expression f(t) is defined as:

t represents a real parameter.

Expanding  f(t) yields:

Cauchy schwarz inequality

This simplifies to:

Cauchy schwarz inequality

Where

Cauchy schwarz inequality

Cauchy schwarz inequality

2. Non-negativity of :

As f(t) is a sum of squares, it is always non-negative.

Cauchy schwarz inequality

3. Discriminant condition:

For the quadratic equation 𝑓(𝑡)=0, the discriminant must satisfy:

Simplifying, we get:

Cauchy schwarz inequality

or equivalently:

Substituting the definitions of 𝑎, 𝑏, and 𝑐 yields:

4. Equality condition: Equality occurs when the discriminant Δ=0, which occurs when 𝑢_ 𝑖 ​and 𝑣_ 𝑖  are linearly dependent, i.e.,  u=kv for some scalar  k.

This completes the proof of the Cauchy-Schwarz inequality.

The Cauchy  inequality is a fundamental result in linear algebra and analysis. It states: For vectors u,v ∈R^n or C^n:

Cauchy schwarz inequality

where

is the dot product and is the Euclidean norm.

Example 1: Real numbers

Let u=(1, 2, 3) and v=(4, -1, 2)

  • Compute ⟨u,v⟩:

  • Compute ∥u∥ and ∥v∥:

  • Verify the inequality:

The Cauchy-Schwarz inequality is valid when 8 ≤ 294.

Example 3: Continuous Functions

Let and on the interval . The inner product is defined as:

  • Calculate  ⟨f,g⟩ :

Cauchy schwarz inequality

  • Calculate  ∥f∥ and ∥g∥.

Cauchy schwarz inequality

  • Verify the inequality.Cauchy schwarz inequality

Since the inequality holds.

Why is Cauchy-Schwarz inequality important?

The Cauchy–Schwarz Inequality is fundamental to many mathematical and scientific disciplines. Here are some places where it plays a crucial role:

Geometry of Vectors: It allows you to compute the cosine of the angle between two vectors, which leads to the concept of orthogonality.

Linear algebra is essential for demonstrating other inequalities, such as the triangle inequality in normed spaces.

Statistics: The inequality underpins the covariance and correlation measures of random variables.

Optimization is commonly utilized in problem solving and algorithm analysis.

 

 

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Cramer’s rule 2×2 problems

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Cramer's rule 2x2

Cramer’s rule 2×2 , 3×3 is a method used to solve systems of linear equations using determinants. So  It applies to systems of  n linear equations with n variables, assuming that the determinent of the co-efficient matrix is non zero. This rule provides precise formulas for solving a system of linear equations using determinants.

Consider this system of linear equations:

Cramer's rule 2x2

where:

  •  A is a square matrix (with size n×n)
  • x is a column vector of unknowns x_1,x_2,…,x_ n​,
  • b represents a column vector of constants. b_1,b_2,…,b_n

The matrix equation can be written as:

Cramer's rule 2x2

Step-by-Step Instructions for Cramer’s rule 2×2

1. Calculate the determinant of the coefficient matrix: Check if matrix A’s determinant (det(𝐴)) is non-zero. Because if det(A) = 0, the system lacks a unique solution and cannot be solved using Cramer’s Rule.

2. Construct Matrices A_1, A_2,…, A_n​: For each unknown x_i​, construct a new matrix  A_i​ by substituting the i-th column of matrix A with the column vector b. Substitute the constants from vector b for the i-th column of A to produce the i-th matrix A_i.

  • is formed by replacing the first column of A with b
  • A2 is created by substituting b for A’s second column.
  • and so on for all columns.

3. Calculate the determinants of the modified matrix: Determine the determinant of each matrix A i​, denoted as  det(A_i​), for each  i=1, 2,…,n.

4. Solve for Each x_i: The solution for each unknown x_i is given by:

Cramer's rule 2x2

for i=1,2,…,n.

For example:

Consider this system of linear equations:

The coefficient matrix is:

The column vector b is

Cramer's rule 2x2

Step 1: Firstly, Calculate det(A)

Step 2: Create matrices A_1 and A_2.

  • For x, replace the first column of A with b:
  • For y, change the second column of A to b:

Cramer's rule 2x2

Step 3: Compute the determinants of A_1 and A_2

then,

Step 4: Solve for x and y:

Cramer's rule 2x2

So, lastly, the solution to the system is:

Cramer’s rule 2×2 simplifies the process of solving linear equations using determinants. However, it is computationally expensive for big systems due to the necessity to calculate numerous determinants.

Practice problems

1.

2.

3.

4.

 

 

 

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Descartes’ Rule of Signs: A Guide to Determining Real Roots

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Descartes' Rule of Signs

Finding the real roots of polynomials is one of the most difficult problems to solve, especially if modern numerical methods are not used. While the Rational Root Theorem and synthetic division can help, Descartes’ Rule of Signs provides a simple yet effective method for estimating the number of positive and negative real roots of a polynomial. In this blog, we’ll look at Descartes’ Rule of Signs and how it might aid in polynomial analysis.

What is Descartes’ Rule of Signs?

Descartes’ Rule of Signs is a mathematical principle that determines the number of positive and negative real roots of a polynomial. It works by counting sign changes in the polynomial’s coefficient sequence. Observing these sign shifts allows us to forecast the number of real roots but not their exact quantities without having to solve the polynomial directly.

The Rule Explained

The rule consists of two main parts: determining the number of positive real roots and the number of negative real roots.

1. Positive Real Roots:
To determine the number of positive real roots, use the following steps:

  • Write the polynomial in standard form, with terms sorted in descending order of powers of x.
  • Consider the signs of the polynomial’s coefficients.
  • Count the number of sign changes between successive coefficients.
  • If the coefficient sequence changes from positive to negative or negative to positive, this counts as one sign change.
  • Descartes’ Rule states that the number of positive real roots is either equal to the number of sign shifts or less by an even number. This means that if there are 4 sign changes, the polynomial can have 4, 2, or 0 positive real roots

2. Negative Real Roots:
To get the number of negative real roots, use these steps:

  • Replace  x with  −x in the polynomial.
  • Write a new polynomial P(−x) and check the coefficients’ signs.
  • Count the number of sign changes in the coefficient sequence of P(−x).
  • As with positive real roots, the number of negative real roots will either be equal to the number of sign changes or less by an even number.

Example of Descartes’ Rule of Signs

Let’s take a polynomial and apply Descartes’ Rule of Signs:

Descartes' Rule of Signs

 

Step 1: Determine the Number of Positive Real Roots.
The coefficients are 1, -6, 12, -18, and 9.
1,−6,12,−18,9.

Signs are as follows: +, −, +, −, +
There are four sign changes: + → − , – → + , + → − , and  −→+.
According to Descartes’ Rule, the number of positive real roots is either 4, 2, or zero.

Step 2: Determine the number of negative real roots.
Substitute −𝑥 for x in the polynomial:


The coefficients of P(−x) are 1, 6, 12, 18, and 9.

The signs are all +, indicating no sign changes.
Thus, the polynomial has no negative real roots.

Interpretation of Results
Descartes’ Rule of Signs applies to the polynomial

  • It has 4, 2 , or 0 positive real roots.
  • It has zero negative real roots.

While Descartes’ Rule does not specify the number of roots, it does present a range of possibilities that can serve as a good starting point for further research or numerical procedures.

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De moivre’s theorem proof

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De moivre's theorem

De moivre’s theorem offers an effective method for raising complex numbers to any integer or fractional power. Let’s look at the proof for many cases: When n is a positive integer, negative integer, or fractional number.

Case 1: When is a Positive Integer

The general form of De moivre’s theorem is

Consider the complex number  z=r(cosθ+isinθ), where  r is the modulus and  θ is the argument (angle).

De Moivre’s theorem for positive integer powers will be proven using mathematical induction.

Base Case:

For , we have:

De moivre's theorem

This is clearly accurate, as the equation is precisely the polar form of the complex number.

Inductive Step: Assume the theorem is true for an integer 𝑛 = 𝑘, i.e.

De moivre's theorem

To establish that the theorem applies to n=k+1. We have:

Expanding  this:

Using the product-to-sum formulas for trigonometric functions:

De moivre's theorem

Thus, we have:

De moivre's theorem

This demonstrates that De Moivre’s Theorem is valid for  n=k+1, completing the induction.

Case 2: When n is a Negative Integer

If  n is a negative integer and  m is a positive integer, we can express the negative power as:

De moivre's theorem

Now, apply De Moivre’s Theorem to the positive integer case:

De moivre's theorem

Thus,

Since cos⁡(−mθ)=cos⁡(mθ) and sin⁡(−mθ), we get:

De moivre's theorem

Thus, for negative integer powers, De Moivre’s Theorem remains valid, and we have:

Case 3: When n is a Fraction (Positive or Negative)

Consider the scenario when  n is a fraction, say  n= q /p​, where  p and q are integers.

De Moivre’s formula can be applied to fractional exponents by taking the n-th roots of a complex number.

For a fractional power n=p/q, we define:

De moivre's theoremDe moivre's theorem

This formula is valid assuming that we are dealing with the argument’s principal value and that the fractional exponent results in a single principal root.

When 𝑛 is fractional, the trigonometric functions’ periodicity creates numerous alternative values (branches) for the argument. Specifically, the generic solution for fractional exponents introduces a collection of solutions provided by:

De moivre's theorem

where k=0,1,2,…,q−1. This represents all the distinct -th roots of z^p, corresponding to the multiple possible values for z^(p/q)

 

 

 

 

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